SOLUTION: slove algebraically log5 + log (4-2x)= log(x-1)
Algebra.Com
Question 63851: slove algebraically log5 + log (4-2x)= log(x-1)
Answer by rahman(247) (Show Source): You can put this solution on YOUR website!
log5 + log (4-2x)= log(x-1)
20-10x=x-1
20+1=10x+x
21=11x
ok
RELATED QUESTIONS
solve algebraically:... (answered by rapaljer)
slove algebraically log base 4 (x+41)- log base... (answered by funmath,rahman)
log5(2x-)+1=log... (answered by stanbon)
Log(4x)=log5+log(x-4) (answered by lwsshak3)
log(x-4)+log5=2 (answered by Theo)
solve log(x-4) + log(x+5)=1 algebraically
(answered by solver91311)
Log(5) - log (x) + log5 =(1/10) log... (answered by MathTherapy)
please help me solve... (answered by nerdybill)
slove for x:
log (x+2) - log (x-1)= log 4
3 (answered by rapaljer)