SOLUTION: slove algebraically log base 4 (x+41)- log base 4(2x-5)=2
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Question 63849: slove algebraically log base 4 (x+41)- log base 4(2x-5)=2
Found 2 solutions by funmath, rahman:
Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
slove algebraically log base 4 (x+41)- log base 4(2x-5)=2
log base 4((x+41)/(2x-5))=2 because log(a)-log(b)=log(a/b) if the bases are the same.
because log base a (b)=x ==> a^x=b
Check:
log base 4 (121/31+41)-log base 4 (2(121/31)-5)=2
log base 4 (1392/31)-log base 4 (87/31)=2
log base 4 ((1392/31)/(87/31))=2
log base 4((1392/31)(31/87))=2
log base 4(1392/87)=2
log base 4 (16)=2
log base 4 (4^2)=2
2=2 We're right!!!
Happy Calculating!!!
Answer by rahman(247) (Show Source): You can put this solution on YOUR website!
log base 4 (x+41)- log base 4(2x-5)=2
log base 4 (x+41)- log base 4(2x-5)=log base 4 (4^2)
log base 4 (x+41)- log base 4(2x-5)=log base 4 (16)
log base 4 =log base 4 (16)
Ok
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