SOLUTION: Solve the equation 7^(x 2) = 5^x. Round the answer to four decimal places.
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Question 623003: Solve the equation 7^(x 2) = 5^x. Round the answer to four decimal places.
Found 2 solutions by MathTherapy, lwsshak3:
Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!
Solve the equation 7^(x 2) = 5^x. Round the answer to four decimal places.
(x - 2) log 7 = x log 5
x - 2 = 0.827087475x ----- Cross-multiplying
x - 0.827087475x = 2
.172912525x = 2
, or 11.56654212 ≈
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Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Solve the equation 7^(x 2) = 5^x. Round the answer to four decimal places.
**
7^(x 2) = 5^x
take log of both sides
(x-2)log7=xlog5
(x-2)/x=log5/log7≈.8271
x-.8271x=2
.1729x=2
x≈2/.1729
x≈=11.5665
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