SOLUTION: please help solve the equation.
log6 (x2 - 5x) = 1
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Question 617626: please help solve the equation.
log6 (x2 - 5x) = 1
Found 2 solutions by stanbon, solver91311:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
solve the equation.
log6 (x^2 - 5x) = 1
-----
x^2-5x = 6^1
---
x^2-5x-6 = 0
Factor:
(x-6)(x+1) = 0
x = -1 or x = 6
Both are acceptable solutions.
=================
Cheers,
Stan H.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
In the future use the underscore character to indicate subscripts and the caret to indicate superscripts so that it isn't so difficult to figure out what you are trying to communicate. E.g. log_6(x^2 - 5x) = 1 clearly communicates:
\ =\ 1)
Use the definition of logarithms:
\ =\ y\ \Leftrightarrow\ b^y\ =\ x)
So
which is to say:
Solve the quadratic for the two roots. Check both solutions in the original equation to make sure you aren't including an extraneous root.
John
My calculator said it, I believe it, that settles it
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