SOLUTION: If logN= logA + 3logB, solve for N in terms of A and B.
Algebra.Com
Question 616893: If logN= logA + 3logB, solve for N in terms of A and B.
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
If logN= logA + 3logB, solve for N in terms of A and B.
.
logN= logA + 3logB
logN= logA + logB^3
logN= logAB^3
N= AB^3
RELATED QUESTIONS
If log N = (1/2)loga+3logb-2logc then express N in terms of a, b, and c. (answered by lwsshak3)
I am asked to express in terms of log m and log n... (answered by Theo)
write x in terms of a,b and c log x=2log a-(3logb(1/2)log... (answered by lwsshak3)
If (N^17) = 2012 and the decimal representation of logN is 0.ABCDE... (where A, B, C, ... (answered by ikleyn)
2. The expression log(3+x) is undefined for what values of x?
3. If loga = (1/3)logx - (answered by robertb)
Write as a single logarithm
a) loga+logb-logc
b) loga+3logb-1/2logc
Can you please... (answered by lwsshak3)
solve... (answered by neatmath)
If loga 2 = 0.3 and loga 3 = 0.48, solve for the exact value of log6... (answered by ikleyn)
1.the exact value of log4[log3(log28)]
2. If log3 = A and log7 = B, find (log base of (answered by stanbon)