SOLUTION: Solve for x: log (x - 6) base of 2 = 3 - log 4 base of 2
Algebra.Com
Question 616501: Solve for x: log (x - 6) base of 2 = 3 - log 4 base of 2
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Solve for x:
log (x - 6) base of 2 = 3 - log 4 base of 2
log2(x-6)=3-log2(4)
log2(x-6)+log2(4)=3
log2[(x-6)*4]=3
convert to exponential form
2^3=4(x-6)=8
4x-24=8
4x=32
x=8
RELATED QUESTIONS
solve for x:
log 2 (log 3 x) = 4 -----> log of (log of x base 3) base 2 equals 4
(answered by jsmallt9)
how do you solve log base 4 (log base 3 (log base 2 of X)) = 0??
(answered by stanbon)
solve for x:
log base 3 (7x+4)-log base 3 of 2 = 2logbase3 of... (answered by stanbon,josmiceli)
Solve for x
log (base of 2)(x^2+8) = log (base of 2)x + log(base of 2)... (answered by edjones)
Solve for x:
A.) Log(base 3)4 + log(base 3)5 = log(base 3)(4x+5)
B.)log(base 7)6... (answered by algebrapro18)
log base 16 of x + log base 4 of x + log base 2 of x = 7
solve for... (answered by lwsshak3)
Solve for x:
(A.) (5/2) log(base 4)4 = log(base 4)(2x-3)
(B.) Log(base 3)(x+2)-... (answered by stanbon)
log(base 4)X+log(base 4)(X+6) = 2
solve for... (answered by ewatrrr)
solve:
log 4 base 2 - log (x+3) base 2 = log 8 base... (answered by lwsshak3)