SOLUTION: Hello, I was wondering if you may be able to help me with this problem, I've tried applying what I know, but it doesn't seem to come out right...
(1/9)^3x=27
So what I've tried
Algebra.Com
Question 615239: Hello, I was wondering if you may be able to help me with this problem, I've tried applying what I know, but it doesn't seem to come out right...
(1/9)^3x=27
So what I've tried is...
1. Setting the bases equal
So, basically,
3^2(-3x)=3^3
**I did (-3x) because it's under a 1 in the original problem, I feel that this may be where I am having issues.
2.Solve for X.
2(-3x)=3
-6x=3
x=-2
However when I try to check my work, the problem just doesn't seem to come out right with X being -2. I would greatly appreciate your time and help! Many regards, -Sarah.
Found 3 solutions by Earlsdon, Alan3354, josmiceli:
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
You've done everything correctly except the final step:
You had:
What it should be is:
Divide both sides by -6.
Simplify.
Check this out as a solution!
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
-6x = 3
x = -1/2
----------
You had it right, except for the last step
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Note That , so
I can take the cube root of both sides
-----------
check:
RELATED QUESTIONS
Hello, im wondering if you can help me figure out the formula to find:
If 6750 red... (answered by Boreal,alanc)
Hi, I am confused about this problem and was wondering if you could help me.
Solve the (answered by josgarithmetic)
I was wondering if you would be able to assist me with this problem...
y=x^2-2x-9
(answered by edjones)
I'm having difficulty with this problem.
-6(5X+2)=198 I was wondering if you could solve (answered by checkley71)
Hi! I was wondering, I know this may be kind of elementary and seem like a stupid... (answered by Nate)
I'm using a book called No-Nonsense Algebra by Richard Fisher. I've run into a problem... (answered by MathLover1,math_helper)
Hello,
I was wondering if you would be able to help me out on this problem. I'm not... (answered by swincher4391)
Hello, i was wondering if someone could help me out with this word problem. Im very... (answered by josgarithmetic)
Hello, I was wondering if you can help me out this summer.
You see next year I am going... (answered by nyc_function)