SOLUTION: my question is y varies jointly as m and the square of n and inversely as p. y =15 when m=2, n=1, and p=6. Find y when m=3, n=4 and p=10

Question 61141: my question is
y varies jointly as m and the square of n and inversely as p. y =15 when m=2, n=1, and p=6. Find y when m=3, n=4 and p=10
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
y varies jointly as m and the square of n and inversely as p. y =15 when m=2, n=1, and p=6. Find y when m=3, n=4 and p=10
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y=k[mn^2/p]
Need to find "k".
15=k[2*1^2/6]
k=45
EQUATION:
y=45[mn^2/p]
Now find y when m=3,n=4,p=10.
y=[3*4^2/10]
y=4.8
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Cheers,
Stan H.

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