# SOLUTION: I'm doing homework and I wasn't able to get to class because I was out of town. I have the worksheet, it tells me to Use the CHANGE OF BASE formula to evaluate the following. L

Algebra ->  Algebra  -> Exponential-and-logarithmic-functions -> SOLUTION: I'm doing homework and I wasn't able to get to class because I was out of town. I have the worksheet, it tells me to Use the CHANGE OF BASE formula to evaluate the following. L      Log On

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 Question 597170: I'm doing homework and I wasn't able to get to class because I was out of town. I have the worksheet, it tells me to Use the CHANGE OF BASE formula to evaluate the following. Log2 (10)=x Log12 (1243)=x Most of the problems are like this. I looked at examples online, but none of the examples are set up like this. What I have been doing is just setting the problem up differently for example Log2 (10)=x would be 10=2^x and I'm really really confused. I need help. Please someone respond. ThanksFound 2 solutions by stanbon, AnlytcPhil:Answer by stanbon(57246)   (Show Source): You can put this solution on YOUR website!Log2 (10)=x Log12 (1243)=x ---- Change of base Formula: log(Base A)B = [log(base C)B] / [log(base C)A] Note: The "C" can be any positive number. --- Your Problems: x = log(10)/log(2) = 1/0.3010 = 2.3219 --------------- x = log(1243)/log(2) = 10.2796 ================================== Cheers, Stan H. Answer by AnlytcPhil(1276)   (Show Source): You can put this solution on YOUR website!```The change of base formula is: = or = Therefore = x = = = .3010299957 or you can use: = x = = = .3010299957 = .3010299957 ------------------------ Log12 (1243)=x = x = = = 2.867424856 or you can use: = x = = = 2.867424856 ------------------- Notice that you may use either "log" (which is base 10) or "ln" (which is base "e"). Both are on your calculator. The numbers you divide will be different but when you divide them you will always get the same answer either way. Edwin```