SOLUTION: How do you solve the following equation: 3logbase(2)X+1=7
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Question 596808: How do you solve the following equation: 3logbase(2)X+1=7
Found 2 solutions by lwsshak3, solver91311:
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
How do you solve the following equation:
3logbase(2)X+1=7
3log2(x)+1=7
log2(x^3)=6
x^3=2^6 (exponential form)
take cube root of both sides
x=2^2
x=4
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
There are two ways to interpret the problem as you rendered it.
You either meant:
\ =\ 7)
the solution to which would make a fiend from the seventh circle of Hell look attractive, or you meant:
\ +\ 1\ =\ 7)
the solution to which is nice, neat, and only involves integers. I'm going for the simple way since, at this point, I have 51% of the vote.
Add -1 to both sides:
\ =\ 6)
Multiply both sides by 
\ =\ 2)
Use the definition of the logarithm function
 \ \ \Rightarrow\ \ b^y = x)
to write:
\ =\ 2 \ \ \Rightarrow\ \ 2^2 = x)
John
My calculator said it, I believe it, that settles it
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