SOLUTION: Write as a single log of a single base.
3log[e]24 - ln36 - ln16
Algebra.Com
Question 594305: Write as a single log of a single base.
3log[e]24 - ln36 - ln16
Answer by mamiya(56) (Show Source): You can put this solution on YOUR website!
3log[e]24 - ln36 - ln16 = 3ln24 - ln36 - ln16
= ln (24^3) - ( ln36 + ln16 )
= ln 13824 - ln ( 36*16)
= ln 13824 - ln 576
= ln ( 13824/576)
= ln 24
so 3log[e]24 - ln36 - ln16 = ln(24)
RELATED QUESTIONS
Help.
4 log base of 5 (x+3)-3log base of 5 w
write as a single... (answered by scott8148)
write 1 - 3log(base 5) x as a single... (answered by rapaljer)
Write as single log: 3log base 4 argument x squared + 2log base 4 argument... (answered by ankor@dixie-net.com)
write 3log u - log v - 4log z expression as a single... (answered by stanbon,Theo)
Write the logarithmic expression
3log x – 2log y + log z
as a single... (answered by ikleyn)
Express as a single logarithm log 11 - log 6 + 1/3log 8 + 1/3log... (answered by josmiceli)
write as a single logarithm 3log x+2log... (answered by dnanos,josmiceli)
Please help me write this expression as a single logarithm: 3log base 4 of x^2 + 1/2log... (answered by lwsshak3)
write the expression (log base of b)(2y+5)-4(log base of b)(y+3) as a single... (answered by Theo)