SOLUTION: This is the question:
log(base 5) 125^1/2 + log(base 11) 121^1/3= 13/6
What I tried:
log(base 5) 125^1/2 + log(base 11) 121^1/3 = 13/6
log(base 5) 5*5^1/2+ log (base11) 121^
Algebra.Com
Question 581754: This is the question:
log(base 5) 125^1/2 + log(base 11) 121^1/3= 13/6
What I tried:
log(base 5) 125^1/2 + log(base 11) 121^1/3 = 13/6
log(base 5) 5*5^1/2+ log (base11) 121^1/3= 13/6
Yup,unfortunately, I'm stuck at here.
Thanks in advance ^0^!!
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
log(base 5) 125^1/2 + log(base 11) 121^1/3= 13/6
log(base 5) (5^3)^1/2 + log(base 11) (11^2)^1/3= 13/6
log(base 5) (5^3/2) + log(base 11) (11^2/3)= 13/6
3/2 + 2/3= 13/6
9/6 + 4/6= 13/6
13/6 = 13/6
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