SOLUTION: How do you solve for E in the following equation? 9=0.67log(0.37E)+1.46

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: How do you solve for E in the following equation? 9=0.67log(0.37E)+1.46      Log On


   

Question 575203: How do you solve for E in the following equation?
9=0.67log(0.37E)+1.46
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+9+=+.67+%2A+log%28+.37E+%29+%2B+1.46+
+9+-+1.46+=+.67%2A+log%28+.37E+%29+
+7.54+%2F+.67+=+log%28+.37E+%29+
+log%28+.37E+%29+=+11.2537+
+log%28+.37+%29+%2B+log%28+E+%29+=+11.2537+
+-.4318+%2B+log%28+E+%29+=+11.2537+
+log%28+E+%29+=+11.6855+
+E+=+10%5E11.6855+
+E+=+4.8473%2A10%5E11+
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check answer:
+9+=+.67+%2A+log%28+.37%2A4.8473%2A10%5E11+%29+%2B+1.46+
+9+=+.67+%2A%28+log%28.37%29+%2B+log%284.8473%29+%2B+11+%29+%2B+1.46+
+9+=+.67%2A%28+-.4318+%2B+.6855+%2B+11+%29+%2B+1.46+
+9+=+.67%2A+11.2537+%2B+1.46+
+9+=+7.534+%2B+1.46+
+9+=+8.99998+
close enough