SOLUTION: Given logk 3=7, logk 4=13, and logk 5=22, find logk (12/5k^3)^2

Algebra ->  Algebra  -> Exponential-and-logarithmic-functions -> SOLUTION: Given logk 3=7, logk 4=13, and logk 5=22, find logk (12/5k^3)^2      Log On

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Question 567785: Given logk 3=7, logk 4=13, and logk 5=22, find logk (12/5k^3)^2
Answer by solver91311(13326) About Me  (Show Source):
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Use

The sum of the logs is the log of the product, the difference of the logs is the log of the quotient, and the log of something to a power is the power times the log:







to write:



Then substitute the values you were given plus the fact that to write:



And do the arithmetic.

John

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