SOLUTION: solve for x: log2(x+2) + log2(x+6)=5

Question 567762: solve for x: log2(x+2) + log2(x+6)=5
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
solve for x:
log2(x+2) + log2(x+6)=5
log2[(x+2)(x+6)]=5
convert to exponential form: base(2) raised to log of number(5)=number(x+2)(x+6)
2^5=x^2+8x+12
32=x^2+8x+12
x^2+8x-20=0
(x+10)(x-2)=0
x=-10(reject, x>0)
or
x=2
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