SOLUTION: Potassium 42 has a decay rate of approximately 5.5% per hour, assuming an exponential decay model, fine the number of hours it will take for the original quantity of potassium 42 t
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Question 566011: Potassium 42 has a decay rate of approximately 5.5% per hour, assuming an exponential decay model, fine the number of hours it will take for the original quantity of potassium 42 to b halved?
Found 2 solutions by stanbon, KMST:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Potassium 42 has a decay rate of approximately 5.5% per hour, assuming an exponential decay model, find the number of hours it will take for the original quantity of potassium 42 to b halved?
----
y = ab^x
---
(1/2)a = a*b^x
---
1/2 = b^x
---
1/2 = 0.945^x
x = log(1/2)/log(0.945)
--
x = 12.25 years
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Cheers,
Stan H.
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Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
The decay function could be represented as
fraction remaining remaining=
With in hours, we know that at , fraction remaining=
<--->
We want to find t so that 50% is left, so
<--->
Combining both equations
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