SOLUTION: find the minimum value of y=x2-22x+132
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Question 550093: find the minimum value of y=x2-22x+132
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
find the minimum value of y=x^2-22x+132
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Minimum occurs when x = -b/(2a) = 22/(2) = 11
f(11) = 11^2-22*11+132 = 121-242+132 = 11
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Minimum: (11,11)
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Cheers,
Stan H.
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