SOLUTION: how do we solve log16-log2x=4?
Algebra.Com
Question 545106: how do we solve log16-log2x=4?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
solve log(16) - log(2x) = 4
subtraction means divide, so write
= 4
Simplify,cancel 2
= 4
write the exponent equiv of logs
=
10000x = 8
x =
x = .0008
:
:
Check this on your calc: enter log(16) - log(2*.0008), results: 4
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