SOLUTION: solve log(3x+4)=2log(x)

Question 507520: solve log(3x+4)=2log(x)
Found 2 solutions by nerdybill, Earlsdon:
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
log(3x+4)=2log(x)
log(3x+4)=log(x^2)
3x+4 = x^2
0 = x^2 - 3x - 4
0 = (x-4)(x+1)
x = {4, -1}
we can throw out the -1 solution (extraneous) leaving:
x = 4

Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Solve:
Apply the "power rule" to the right side.
Now if then so...
Rearrange as:
Solve by factoring:
Apply the "zero product" rule:
or so that...
or
Now you must check the results for "extraneous" or "invalid" values:
Try
Substitute

This is not valid!
Try
Substitute

This is valid.
Solution is
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