SOLUTION: (4^-1 + 2^-1)^2 I know that i have to apply the negative exponent property to each term, and then get a common denominator and add, but that is about all i can figure out.

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Question 479480: (4^-1 + 2^-1)^2
I know that i have to apply the negative exponent property to each term, and then get a common denominator and add, but that is about all i can figure out.

Found 2 solutions by stanbon, Edwin McCravy:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
(4^-1 + 2^-1)^2
-----
[(1/4) + (1/2)]^2
----
[(2+4)/8]^2
-----
= (3/4)^2
----
= 9/16
=============
Cheers,
Stan H.

Answer by Edwin McCravy(20060)   (Show Source): You can put this solution on YOUR website!


(4-1 + 2-1)2

I'll do it different from the way the other tutor did it, just
to illustrate another method:

Let's wait till later to apply the negative exponent property:
Let's write 4 as 22

[(22)-1 + 2-1]2

(2-2 + 2-1)2

(2-2 + 2-1)(2-2 + 2-1)

Us FOIL and add exponents to multiply

2-4 + 2-3 + 2-3 + 2-2

Combine the middle two terms as 2 of them

2-4 + 2×2-3 + 2-2

Add exponents in the middle term

2-4 + 2-2 + 2-2

Now the middle and last terms can be combined as two of them: 

2-4 + 2×2-2

Add exponents to simplify the second term:

2-4 + 2-1

Finally we apply the negative exponent property:

 + 

 + 

Get a LCD of 16

 +  

 + 



Edwin







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