SOLUTION: The initial population of a town is 127,866 and it grows with a doubling time of 12 years. What will the population be in 33 years?

Question 472433: The initial population of a town is 127,866 and it grows with a doubling time of 12 years. What will the population be in 33 years?
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
The initial population of a town is 127,866 and it grows with a doubling time of 12 years. What will the population be in 33 years?
.
assuming exponential growth:
a = pe^(rt)
first, we need to find r (rate of growth)
2(127866) = 127866e^(r*12)
2 = e^(r*12)
ln(2) = 12r
ln(2)/12 = r
.
Our general formula:
a = 127866e^(ln(2)/12 * t)
.
subsitute 33 for t:
a = 127866e^(ln(2)/12 * 33)
a = 127866e^(1.9062)
a = 127866(6.7272)
a = 860176

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