Hi,

f(x) = x3 + 5x2 + 6x + 2  | x = -1 a root as -1 + 5 - 6 + 2 = 0

Using synthetic division

(x3 + 5x2 + 6x + 2)/(x+1) = x^2 + 4x + 2 



-1	1	5	6	2

		-1	-4	-2

	1	4	2	0

(x+1)(x^2 + 4x + 2)

   



zeros are: -1, -2+sqrt(2),-2-sqrt(2) 

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