Hi,

(2x3 - 23x2 + 71x - 30)/(x-5) = 2x^2 -13x + 6

Using synthetic division to determine the 2x^2 -13x + 6

5	2	-23	 71	-30

		 10	-65	 30

	2     -13	  6	  0



(x-5)(2x^2 - 13x + 6) = 0

factoring

(x-5)(2x -1)(x-6) = 0

(x-5)= 0     x= 5

(2x -1)= 0   x= 1/2

(x-6) = 0    x= 6 

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