You can
put this solution on YOUR website!
Hi,
invest $130 at 4% compounded continuously
A = Pe^(rt) where P is the amount Invested, r the rate, t the number of years
$600 = $130 e^.04t
ln(600/130) = .04t
1.5294/.04 = t
38.2349yrs = t
You can
put this solution on YOUR website!The compounding continuously formula is:

, where P is the
initial investment, r is the interest rate, and t the amount of time in years the
investment is held. To find in how many years the initial investment of $130 will
reach $600, we substitute in our formula A(t)=600, and get:

, solving this equation we get:

<=>

, taking the natural logarithms of both sides, we have

, and final

or t=38 years.