SOLUTION: Solve for x. 2 log x - log 2x = .301 And The Answer Can't Be A Dec.

Algebra ->  Algebra  -> Exponential-and-logarithmic-functions -> SOLUTION: Solve for x. 2 log x - log 2x = .301 And The Answer Can't Be A Dec.      Log On

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Question 449778: Solve for x.
2 log x - log 2x = .301
And The Answer Can't Be A Dec.

Answer by Alan3354(30993) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for x.
2 log x - log 2x = .301
-------------------
log%28x%5E2%29+-+log%282x%29+=+.301
log(x/2) = .301
x/2 = 10^0.301
x = 2*10^0.301
---------------
x =~ 3.99972
If you meant for 0.301 to be the log(2), then it's
x = 4
Otherwise, the answer is what it is, and saying it can't be something is senseless.