SOLUTION: Solve for x.
2 log x - log 2x = .301
And The Answer Can't Be A Dec.
Algebra.Com
Question 449778: Solve for x.
2 log x - log 2x = .301
And The Answer Can't Be A Dec.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Solve for x.
2 log x - log 2x = .301
-------------------
log(x/2) = .301
x/2 = 10^0.301
x = 2*10^0.301
---------------
x =~ 3.99972
If you meant for 0.301 to be the log(2), then it's
x = 4
Otherwise, the answer is what it is, and saying it can't be something is senseless.
RELATED QUESTIONS
Solve for x:
a) log base4 (x+2) + log base4 (n-4)=2
b) log base2 (x^2-2) - log base2... (answered by stanbon)
How do I solve the following for x?
log(base2)9 / log(base2)3 = log(base2)2x
I tried... (answered by lwsshak3)
Solve log(2x+3) = log(4x) + 2 for... (answered by stanbon)
Solve log(2x – 3) + log(2) = 1 for x.
(answered by nerdybill)
2log(x+1)-log(x+2)=log(2x-1)
base log 10
answer=1.3028
Can sir show me the... (answered by lwsshak3)
solve for x... (answered by Alan3354)
solve for x... (answered by jsmallt9)
Solve for x: log(x - 3) = (log x - log... (answered by nerdybill)
Solve for x: log(x-2)+ log x = log... (answered by edjones)