SOLUTION: Solve: (1/5)^(t-2)=125. Round to 4 decimal places if necessary.
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Question 44952
:
Solve: (1/5)^(t-2)=125.
Round to 4 decimal places if necessary.
Answer by
stanbon(57219)
(
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):
You can
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(1/5)^(t-2)=125
Take the natural log of both sides to get:
(t-2)ln(1/5) = ln 125
t-2= ln125/ln(1/5)
t-2= -3
t=-1
Cheers,
Stan H.