SOLUTION: Solve:
log12(m^2 + 73) = log12(17m + 3)
Algebra.Com
Question 446667: Solve:
log12(m^2 + 73) = log12(17m + 3)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Solve:
log12(m^2 + 73) = log12(17m + 3)
---------------
Solve:
m^2+73 = 17m+3
---
m^2-17m+70 = 0
---
Use Inverse-FOIL to Factor:
m^2-10m-7m+70 = 0
------
m(m-10)-7(m-10) = 0
---
(m-10)(m-7) = 0
---
m = 10 or m = 7
===========================
Cheers,
Stan H.
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