SOLUTION: log base 2 (x+3)+ log base 2 (x-1)=5 (solve, list answers as integers or simplified fractions)
x=?
Algebra.Com
Question 443702: log base 2 (x+3)+ log base 2 (x-1)=5 (solve, list answers as integers or simplified fractions)
x=?
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
log base 2 (x+3)+ log base 2 (x-1)=5
log base 2 (x+3)(x-1)=5
(x+3)(x-1)=2^5
x^2+2x-3 =32
x^2+2x-35 = 0
(x+7)(x-5) = 0
x = {-7,5}
The negative answer is "extraneous" -- toss it out leaving:
x = 5
RELATED QUESTIONS
Solve the equation. (Enter your answers as a comma-separated list. If there is no... (answered by Alan3354)
Solve for x:
A.) Log(base 3)4 + log(base 3)5 = log(base 3)(4x+5)
B.)log(base 7)6... (answered by algebrapro18)
log base 2 (x-2)+log base 2(8-x)-log base... (answered by stanbon)
Solve for x:
(A.) (5/2) log(base 4)4 = log(base 4)(2x-3)
(B.) Log(base 3)(x+2)-... (answered by stanbon)
log (base 3) x + log (base 5) 4x =... (answered by josgarithmetic)
find x if log 6 base 3 + log x base 3 - log 5 base... (answered by lwsshak3)
log(base 5)(X+3)-log(base 5)X=2
solve for... (answered by ewatrrr)
Solve for x:
2 log base 5(7-x)-log base 5 3=log base 5... (answered by lwsshak3)
1. Solve the following equations
a) log(base 5)x+2 + log(base 5) x-2 - log(base 5)4 =... (answered by mananth)