SOLUTION: Sorry should have been an equal sign e^(x^2+7x)=(1/e^12)

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Question 437414: Sorry should have been an equal sign
e^(x^2+7x)=(1/e^12)
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Sorry should have been an equal sign
e^(x^2+7x)=(1/e^12)
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Cross-multiply:
e(x^2+7x+12) = 1
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Take the natural log
x^2+7x+12 = 0
(x+3)(x+4) = 0
x = -3 or x = -4
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Cheers,
Stan H.