SOLUTION: Combine 3log(base2)x + 1(over)2log(base8)x - 2log(base2)(x+1) 1(over)2 is a fraction like one-half

Question 436570: Combine
3log(base2)x + 1(over)2log(base8)x - 2log(base2)(x+1)
1(over)2 is a fraction like one-half
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Combine
3log(base2)x + 1(over)2log(base8)x - 2log(base2)(x+1)
---
2log2(x) + (1/2)log8(x) - 2log2(x+1)
---
Note log8(x) = (1/3)log(x)
---
log2(x^2) + (1/6)log(x) -log2(x+1)^2
-------------------
= log2[(x^2*x^(1/6)/(x+1)^2]
--------
= log2[x^(7/6)/(x+1)^2]
===============================
Cheers,
Stan H.
RELATED QUESTIONS
Combine 2log(base8)x - 2(over)3log(base8)x + 4log(base8)x 2(over)3 is a fraction as (answered by ewatrrr)

Write each expression as a single logarithm. a) 2log (base2) x - 4log (base2) y + 3log... (answered by venugopalramana)

Solve: log(base 2) x - 2log(base2) (x-1) =... (answered by lwsshak3)

combine 2log(base8)x - 2/3log(base8)x + 4log(base8) not sure how to combine with... (answered by ewatrrr)

log[base2]x+2log[base2]y=x (answered by Alan3354)

2log 3log x =... (answered by Fombitz)

log(base2)8 + 2log(base2)x =... (answered by lwsshak3)

Solve -2log(base8)(x + 1) =... (answered by lwsshak3)

Use the power, quotient, and product rules of logarithms to rewrite the expression as a... (answered by lwsshak3)