SOLUTION: log3(x-2) = 1+log3(x-4) The logs have a base of 3. How do I solve this?

Algebra ->  Algebra  -> Exponential-and-logarithmic-functions -> SOLUTION: log3(x-2) = 1+log3(x-4) The logs have a base of 3. How do I solve this?      Log On

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Question 433268: log3(x-2) = 1+log3(x-4) The logs have a base of 3. How do I solve this?
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
log3(x-2) = log3(3) + log3(x-4)

x-2 = 3(x-4)

x-2 = 3x - 12

10 = 2x