SOLUTION: Please help! I would really appreciate it!
>Solve the equation (1/3)log7 64+ (1/2)log7 121= log7 x
>Find log3 25 given that log3 5= 1.465
>If log.5=-.3010, what is the man
Algebra.Com
Question 428709: Please help! I would really appreciate it!
>Solve the equation (1/3)log7 64+ (1/2)log7 121= log7 x
>Find log3 25 given that log3 5= 1.465
>If log.5=-.3010, what is the mantissa of log.5?
Please include steps for each! Thanks again
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
\log_7\left(64\right)\ +\ \left(\frac{1}{2}\right)\log_7\left(121\right)\ =\ \log_7\left(x\right))
Use
\ =\ n\log_b(x))
and
to write:
\ +\ \log_7(11)\ =\ \log_7(x))
Use "The sum of the logs is the log of the product"
 + \log_b(y) = \log_b(xy))
to write:
\ =\ \log_7(x))
Use:
\ =\ \log_b(y)\ \Leftrightarrow\ x\ =\ y)
to write:
Sorry, one problem per post.
John
My calculator said it, I believe it, that settles it
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