SOLUTION: Solve: 6^(n+1)>=10. Round to four decimals. Thanks

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Question 42859: Solve: 6^(n+1)>=10. Round to four decimals.
Thanks

Answer by fractalier(6550)   (Show Source): You can put this solution on YOUR website!
From
6^(n+1) ≥ 10
take the log of both sides, apply the power rule and solve for n...we get
log 6^(n+1) ≥ log 10
log 6^(n+1) ≥ 1
(n+1)*log 6 ≥ 1
n + 1 ≥ 1/log 6
n ≥ (1/log 6) - 1
n ≥ .2851

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