SOLUTION: Solve: 6^(n+1) >or= 10. Round to four decimals places. Thanks

SOLUTION: Solve: 6^(n+1) >or= 10. Round to four decimals places. Thanks

Algebra.Com

Question 42554: Solve: 6^(n+1) >or= 10. Round to four decimals places.
Thanks
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
To solve
6^(n+1) ≥ 10
take the log of both sides
log 6^(n+1) ≥ log 10
log 6^(n+1) ≥ 1
(n+1)*log 6 ≥ 1
n+1 ≥ 1/log 6
n ≥ (1/log 6) - 1
n ≥ .2581
RELATED QUESTIONS
Solve: 6^(n+1)>=10. Round to four decimals.... (answered by fractalier)

Solve: 6^n+1 >= 10. Round to four decimal places. a. n >= 0.2851 b. n >= 0.6667 c. n (answered by user_dude2008)

Solve for "X" Round to four decimals places. log base 5 (-3x+1)=... (answered by jsmallt9)

1. uSE LOGORITHMS TO SOLVE FOR GIVEN EQUATION. rOUND THE ANSWER TO FOUR DECIMALS.... (answered by lwsshak3)

Solve 6(n+1 power)≥ 10. Round to four decimal places. This is Greek to me. I'm... (answered by scott8148)

How do you find a solution of the exponential equation, correct to four decimals places. (answered by Earlsdon)

solve each equation. Round to four decimal places.... (answered by Alan3354)

Solve to four decimal places: log(6) 6^9.... (answered by stanbon)

Solve the logarithmic equation for x. (Round your answer to four decimal places.)... (answered by josgarithmetic)