SOLUTION: Solve 64^x<32^(x+2. Thanks
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Question 42249
:
Solve 64^x<32^(x+2.
Thanks
Answer by
fractalier(2101)
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From 64^x < 32^(x+2), we change eveything to powers of two...we get
(2^6)^x < (2^5)^(x+2)
2^(6x) < 2^(5x+10) and then
6x < 5x + 10
x < 10
