SOLUTION: how do you solve log6x+ log6 (x+16)= 2 ?
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Question 421859: how do you solve log6x+ log6 (x+16)= 2 ?
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Presuming you are trying to represent base 6 logs, i.e., )
as opposed to base 10 logs, )
:
First use "The sum of the logs is the log of the product":
\right)\ =\ 2)
Then use the definition of the logarithm function:
 \ \ \Rightarrow\ \ b^y = x)
to write:
Standard form of the quadratic:
The quadratic factors. You can take it from here. You will need to exclude one of the roots because it is not in the domain of the logarithm function.
John
My calculator said it, I believe it, that settles it
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