SOLUTION: Please help me solve {{{lnx+ln(x+3)=1}}}

Algebra.Com
Question 419876: Please help me solve
Found 2 solutions by nerdybill, josmiceli:
Answer by nerdybill(7384)   (Show Source): You can put this solution on YOUR website!





Solve by applying the quadratic formula to give:
x = {0.729, -3.729}
we can throw out the negative solution leaving:
x = 0.729
.
Details of quadratic formula follows:
.
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=19.873127312 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 0.728964294913671, -3.72896429491367. Here's your graph:




Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!
a general rule is:

For example:

Just work the rule backwards
----------------------



Now use the general rule
then,

----------







answer

RELATED QUESTIONS

solve lnx... (answered by josmiceli)
lnx + ln (x+3) =... (answered by nerdybill)
ln(x+3)+lnx=1 (answered by Fombitz)
please help me with this... (answered by Prithwis)
Please help me solve this equation. {{{lnx + ln(x+1)=2}}}. I tried bringing the foil... (answered by jim_thompson5910)
please help me solve this ((( 1/2ln(x+3)-lnx=0... (answered by user_dude2008)
Solve lnx=... (answered by stanbon)
Help me solve by expressing y as a function of x. Cis a positive constant number.... (answered by robertb)
solve for x... (answered by Alan3354,Tatiana_Stebko)