SOLUTION: having difficulty solving the following equation. can you help?
10^x+3 = 6^2x
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Question 418423: having difficulty solving the following equation. can you help?
10^x+3 = 6^2x
Found 2 solutions by ankor@dixie-net.com, solver91311:
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Assume the problem is:
using common logs we have
log equiv of exponents
we know the log of 10 = 1, therefore
x + 3 = 2x*.778
x + 3 = 1.556x
3 = 1.556x - x
3 =.556x
x =
x = 5.393
:
:
Check this on your calc: enter 10^8.393 and 6^10.786, should be close to the same value
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Presuming you mean:
Mainly because
can only be solved by numerical methods,
take the base 10 log of both sides:
\ =\ \log(6^{2x}))
Use the laws of logarithms:
\log(10)\ =\ 2x\log(6))
)
(Because \ =\ 1)
)
The rest is elementary algebra:
\,-\,1})
John
My calculator said it, I believe it, that settles it
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