SOLUTION: 6^3m*6^-m=6^-2m tried 3m*-m=-2m 3m+2m=-m but I think maybe 3m-2m-1m= 0 but not sure how; please show

SOLUTION: 6^3m6^-m=6^-2m tried 3m-m=-2m 3m+2m=-m but I think maybe 3m-2m-1m= 0 but not sure how; please show

Question 416592: 6^3m*6^-m=6^-2m
tried 3m*-m=-2m
3m+2m=-m
but I think maybe 3m-2m-1m= 0 but not sure how; please show

Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Since the bases are all the same, you can add the exponents on the left side to get: 3m+(-m) = 3m-m = 2m

Now you can equate exponents (again, they're all the same) to get: 2m = -2m

Now solve for m to get: 2m+2m = 0 ----> 4m=0 ---> m = 0

So the solution is m = 0

If you need more help, email me at jim_thompson5910@hotmail.com

Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you

Jim
RELATED QUESTIONS
Solve. m�+ 2m� - 3m =... (answered by zeynep)

(2M-6)-(3m-4)= -(-4+M)-4M+6 i started the problem but I'm stuck i got to... (answered by jim_thompson5910,edjones)

44. m^3+2m^2-3m=0 (answered by stanbon,hayek)

m^3+2m^2-3m=0 (answered by jim_thompson5910)

Solve (3m+5)/4 -(2m+6)/6 = m+2 (answered by mathie123)

5m - 2m +8 - 3m +6 =... (answered by jim_thompson5910)

3m+12 over m^2-4=-2m^2+3m+6 over m^2-4+2m-4 over... (answered by Nate)

2m+4-3m=8(m-1) m=... (answered by ReadingBoosters)

(3m / 2m^2 + 7m - 15) + (6 / 2m^2 - 3m) + (2m + 3 / 2m^2 + 17m +... (answered by KMST)