SOLUTION: The directions for the problem is "Solve each equation for x to three significant digits� the problem is {{{ 5^x=3*4^x }}}. I tried changing it to {{{log (3*4^x)

SOLUTION: The directions for the problem is "Solve each equation for x to three significant digits� the problem is {{{ 5^x=34^x }}}. I tried changing it to {{{log (34^x) - log (5^x)=0 }}}

Question 41642This question is from textbook Algebra with trigonometry
: The directions for the problem is "Solve each equation for x to three significant digits� the problem is . I tried changing it to but I couldn�t find anywhere to go after that. I would appreciate if you could help me figure this one out. Please and thanks! This question is from textbook Algebra with trigonometry

Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
Okay from
5^x = 3 * 4^x
take the log and get
log 5^x = log (3 * 4^x)
now apply power rule and multiplication rule and get
x*log 5 = log 3 + x*log 4
x*log 5 - x*log 4= log 3
x(log 5 - log 4)= log 3
x = log 3 / (log 5 - log 4)
then use your calculator
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SOLUTION: The directions for the problem is "Solve each equation for x to three significant digits� the problem is {{{ 5^x=3*4^x }}}. I tried changing it to {{{log (3*4^x) - log (5^x)=0 }}}

SOLUTION: The directions for the problem is "Solve each equation for x to three significant digits� the problem is {{{ 5^x=34^x }}}. I tried changing it to {{{log (34^x) - log (5^x)=0 }}}