# SOLUTION: If log (base of 3) 8=1.8928 and log (base of 3) 2=0.6309, what is the value of log (base of 3) 16?

Algebra ->  Algebra  -> Exponential-and-logarithmic-functions -> SOLUTION: If log (base of 3) 8=1.8928 and log (base of 3) 2=0.6309, what is the value of log (base of 3) 16?      Log On

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 Question 41370This question is from textbook : If log (base of 3) 8=1.8928 and log (base of 3) 2=0.6309, what is the value of log (base of 3) 16?This question is from textbook Answer by venugopalramana(3286)   (Show Source): You can put this solution on YOUR website!If log (base of 3) 8=1.8928 and log (base of 3) 2=0.6309, what is the value of log (base of 3) 16? SINCE ALL ARE TO BASE 3,WE CAN DROP PUTTING THAT AND TAKE IT AS UNDERSTOOD. LOG(16)=LOG(8*2)=LOG(8)+LOG(2)=1.8928+0.6309=2.5237 HENCE LOG(16) TO BASE 3 =2.5237