SOLUTION: Can you please help me with the following:
Assume that log4 ≈ 0.602, log 5 ≈ 0.699 and log 6 ≈ 0.778. Use the properties of logarithms to evaluate each express
Algebra.Com
Question 409441: Can you please help me with the following:
Assume that log4 ≈ 0.602, log 5 ≈ 0.699 and log 6 ≈ 0.778. Use the properties of logarithms to evaluate each expression. Do not use a calculator.
log24
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Assume that log4 ≈ 0.602, log 5 ≈ 0.699 and log 6 ≈ 0.778.
Use the properties of logarithms to evaluate each expression.
Do not use a calculator.
---------
log24 = log(4) +log(6) = 0.602 + 0.778
-----------------------------------
Cheers,
Stan H.
==========
RELATED QUESTIONS
Can you please help to solve the following:
Assume that log 4 ≈ 0.0602, log 5... (answered by stanbon,MathLover1)
Can you please help to solve the following:
Assume that log 4 ≈ 0.0602, log 5... (answered by stanbon,richard1234)
Given that log 2 ≈ 0.301 and log 3 ≈ 0.477, find the following.
log6 27
(answered by jsmallt9)
How do I solve the following:
Assume that Log 4 ≈ 0.602, log 5 ≈ 0.699 and (answered by stanbon,josmiceli)
How do I solve the following:
Assume that Log 4 ≈ 0.602, log 5 ≈ 0.699 and (answered by MathLover1)
Given that log 2 ≈ 0.301 and log 3 ≈ 0.477, find the following
log baseg 8
(answered by Alan3354)
Use log4(7) ≈ 1.4037 and log4 (3) ≈ 0.7925 to approximate the value of each... (answered by jim_thompson5910)
Use log4(7) ≈ 1.4037 and log4 (3) ≈ 0.7925 to approximate the value of each... (answered by josgarithmetic)
If log 2 ≈ 0.301 and log 3 ≈ 0.477, then log 6 ≈
a. 0.778
b. 0.144... (answered by Nate,stanbon)