SOLUTION: how do you solve this system of equation:
y=-2x^2+8x+27
2x+y=15
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Question 40823: how do you solve this system of equation:
y=-2x^2+8x+27
2x+y=15
Answer by zeynep(43) (Show Source): You can put this solution on YOUR website!
y=-2x^2+8x+27
2x+y=15 (move 2x to the right of the equation to leave y alone)
y=15-2x in the first equation write (15-2x)instead of y;
15-2x=-2x^2+8x+27
2x^2-2x-8x+15-27=0
2x^2-10x-12=0 factor out 2 from the trinomial;
2(x^2-5x-6)=0 divide both sides by 2;
x^2-5x-6=0
(x-6)(x+1)=0
x-6=0
x=6 and
x+1=0
x=-1
To find the values of y, we plug in the values of x in ne of the given equations;
for x=6;
2.6+y=15
12+y=15
y=15-12
y=3 and
forx=-1
2.(-1)+y=15
-2+y=15
y=15+2
y=17
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