SOLUTION: Solving logarithmic equations the problem is ln x + ln (x+3) = 1 I first combined the ln ln [x(x+3)] = 1 ln x (squared) + 3x = 1 then I don't know what to do.

Question 403854: Solving logarithmic equations
the problem is ln x + ln (x+3) = 1
I first combined the ln
ln [x(x+3)] = 1
ln x (squared) + 3x = 1
then I don't know what to do.

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
ln x + ln (x+3) = 1
I first combined the ln
ln [x(x+3)] = 1
ln x (squared) + 3x = 1
------------------

e is a constant, ~2.71828
Solve the quadratic for x

Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=19.87312 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 0.728963884857716, -3.72896388485772. Here's your graph:

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