SOLUTION: log(5)625+log(9)(x-3)=6 need help please

Algebra.Com
Question 40006: log(5)625+log(9)(x-3)=6 need help please
Answer by fractalier(6550)   (Show Source): You can put this solution on YOUR website!
Okay, from
log(5)625 + log(9)(x-3) = 6
let us evaluate the left hand log first...
we ask, "What exponent must we raise 5 to to get to 625?" Well, 4. So we have
4 + log(9)(x-3) = 6
log(9)(x-3) = 2
Now convert this to an exponential form...
9^2 = x - 3
81 = x - 3
x = 84

RELATED QUESTIONS

Hello could you please help me simplify: log little3 3/4+ log little3 4/5+ log little3... (answered by Boreal,solver91311,ikleyn,MathTherapy)
Please help! Write 3 log base 5 (x-2) - 2 log base 5 (x+7) + 4 log base 5(x+9) - log... (answered by lwsshak3)
please help me solve this equation: {{{ (3) log(5,( x^2 + 9 )) - 6 = 0... (answered by Alan3354)
please help me solve this log (6x+5) - log (3) = log (2) - log... (answered by solver91311)
hi i need help seriously \ g(x)=-2x+3 find the inverse of the function log^381=x (answered by stanbon)
log { 5 } \sqrt { 625 }... (answered by ewatrrr)
log(x^2+9)-log(x+3)=2+log(x-3) Help... (answered by Edwin McCravy,CharlesG2)
simplify log base 5... (answered by Alan3354)
Can you please help me calculate this? log 3 of 7 + log 3 of 9/7 log 6 of 2 + log 6... (answered by Alan3354)