SOLUTION: (1/16)^x+1=(1/8)^2x-1
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Question 398983
:
(1/16)^x+1=(1/8)^2x-1
Answer by
ewatrrr(24785)
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Hi
4(x+1) = 3(2x-1)
4x + 4 = 6x - 3
7 = 2x
7/2 = x
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