Hi



   (x+3)^2 = 4

  x^2 + 6x + 9 = 4

  x^2 + 6x + 5 = 0

  (x+1)(x+5) = 0  x = -1, the largest solution







2log[4]x+log[4]3=log[4]x-log[4]2

 

     4^0 = 6x      x = 1/6



3^(x+1) = 7^(x-4)

 ln 3^(x+1) = ln 7^(x-4)

(x+1)ln3 = (x-4) ln7

x(ln3 -ln7) = -(4ln7+ln3)

 x = -(4ln7+ln3) /(ln3-ln7) 

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