# SOLUTION: Exoponential Method 1.A biologist is researching a newly-discovered species of bacteria. at time t=0 hours, he puts one hundred bacteria into what he has determined to be a favora

Algebra ->  Algebra  -> Exponential-and-logarithmic-functions -> SOLUTION: Exoponential Method 1.A biologist is researching a newly-discovered species of bacteria. at time t=0 hours, he puts one hundred bacteria into what he has determined to be a favora      Log On

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 Algebra: Exponent and logarithm as functions of power Solvers Lessons Answers archive Quiz In Depth

 Question 393385: Exoponential Method 1.A biologist is researching a newly-discovered species of bacteria. at time t=0 hours, he puts one hundred bacteria into what he has determined to be a favorable growth medium. Six hours later, he measures 450 bacteria. Find an exponential equation thet approximates the information. 2. A \$1,000 deposit is made at a bank that pays 12% compound monthly. How much will you havein your account at the end of 10 years. Answer by ankor@dixie-net.com(15638)   (Show Source): You can put this solution on YOUR website!1.A biologist is researching a newly-discovered species of bacteria. at time t=0 hours, he puts one hundred bacteria into what he has determined to be a favorable growth medium. Six hours later, he measures 450 bacteria. Find an exponential equation that approximates the information. : find k, the growth factor 100*(2^(6/k)) = 450 Divide both sides by 100 2^(6/k) = 4.5 use logs here log(2^(6/k)) = log(4.5) : log(2) = log(4.5) = = 2.17 k = k = 2.765 is the growth factor : A = Ao*2^(t/2.765), the exponential equation where Ao = initial amt A = amt after t hrs t = time in hrs : Check equation using Ao = 100: In a calc enter: 100*2^(6/2.765) results: 450.0 : : 2. A \$1,000 deposit is made at a bank that pays 12% compound monthly. How much will you have in your account at the end of 10 years. : Compound interest formula: A = where A = resulting amt after t years P = principal (\$1000) r = interest rate in decimals (.12) n = no. of time compounded per yr (12 times/yr) t = no. of yrs (10 yrs) : A = : A = : A = on a calc A = \$3300.39