SOLUTION: how do you factor 27x to the third-8?
Algebra.Com
Question 391773: how do you factor 27x to the third-8?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
how do you factor 27x to the third-8?
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That is a "difference of cubes".
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Rewrite as (3x)^3 - 2^3
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Factors:
(3x-2)((3x)^2+(3x)(2)+2^2)
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(3x-2)(9x^2+6x+4)
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Cheers,
Stan H.
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